2^(x+1)*3^x=68

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Solution for 2^(x+1)*3^x=68 equation: 



2^(x+1)*3^x=68

We move all terms to the left:

2^(x+1)*3^x-(68)=0

We move all terms containing x to the left, all other terms to the right

2^(x+1)*3^x=68

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